The at-least-one trap
People multiply or add when they should use 1 − (1 − p)ⁿ. A 10% chance over 10 tries is 65%, not 100%.
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Three modes in one page: simple favorable-over-total probability, the chance of at least one success over several trials, and normal distribution areas.
P = favorable ÷ total · P(at least one) = 1 − (1 − p)ⁿ
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Simple, at least one, or normal distribution.
Favourable and total outcomes; or a single-trial probability and a number of trials; or a mean, standard deviation, and bounds.
Shown as a decimal and a percentage, with the complement so you can see both sides.
Most everyday probability questions are one of these three. Keeping them together saves hunting for the right page.
People multiply or add when they should use 1 − (1 − p)ⁿ. A 10% chance over 10 tries is 65%, not 100%.
Below, above, or between two bounds, computed from the mean and standard deviation directly.
The probability of the event not happening comes free, which is often the number you actually wanted.
The chance that at least one of 200 orders hits a rare failure.
The share of items expected to fall outside a tolerance band, given a mean and standard deviation.
Dice, draws, and coin problems in the simple mode.
Simple: P = favorable ÷ total · At least one: P = 1 − (1 − p)ⁿ · Normal: P = Φ((b − μ)/σ) − Φ((a − μ)/σ)
The at-least-one formula assumes independent trials with the same probability each time. The normal mode uses the standard normal CDF, so it assumes the underlying data is approximately normal.
Divide favorable outcomes by total possible outcomes:
P = favorable ÷ total
Rolling a 4 or higher on a six-sided die is 3 ÷ 6 = 0.5, or 50%.
Work out the chance of it never happening and subtract from 1:
P(at least one) = 1 − (1 − p)ⁿ
With a 10% chance per attempt over 10 attempts, that is 1 − 0.9¹⁰ ≈ 0.651, or about 65%. Adding 10% ten times to reach 100% is the classic error.
The area under a normal curve with your mean and standard deviation: below a value, above a value, or between two bounds.
For a mean of 100 and standard deviation of 15, the probability of a value below 130 is about 0.977.
The chance the event does not happen, which is 1 − P. It is often much easier to compute, which is exactly why the at-least-one formula works the way it does.
No. The at-least-one mode assumes each trial is independent and carries the same probability. Drawing without replacement changes the odds each time, so it needs different maths.
When the data is strongly skewed or bounded, such as income, wait times, or counts near zero. The tail probabilities will be wrong, sometimes badly.
Check the shape with the mean median mode calculator: a mean far from the median is a warning sign.
No. Everything runs locally in your browser.
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